How to convert Char into Date format

If you have the date format in the canonical format, then using the functions over them , will give the expected output.. otherwise it wont't
sample for this in here
Problem stated :convert char format into date format using xdofx:to_char(substr('2008/02/28 00:00:00',1,10),'DD-MON-YYYY') but the conversion is not happening.
if the data in the xml for the date field is good
For ex:
format-date:’2007-07-01T00:00:00.000-06:00’;’DD-MON-YYYY’
you get 01-Jul-2007 as output.
Date should be proper format with timestamp.
in this format YYYY-MM-DDThh:mm:ss+HH:MM.
Even, If you dont want to change the xml data, still you can manipulate things
xdofx:to_date(replace(substr('2008/02/28 00:00:00',1,10),’/’,’-’)||’T00:00:00.000-06:00’,'DD-MON-YYYY')

Hope this helped Madhuri to get what she was expecting :).

Comments

Gabriel Bravo Forero said…
I need to group a Service Request Siebel data by a Created date, but the xml data is like 08/12/2008 13:37:23, but I need to have a SR count day by day. How do I group by an expression like for-each-group:ServiceRequest;./substr(Created,1,10) (That doesn't work)
Sat Sep 19, 04:19:00 AM 2009
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